How do i find the y-intercept of a quadratic formula if there is none?

y = ax squared + bx + c

The variables y and x are graphed on the y and x axes, and a, b and c are constants.

Find the y-intercept for the equation by letting x equal zero. The equation becomes y = 0x squared + 0x + c or y = c.

The y-intercept of a quadratic equation written in the form y = ax squared + bx = c will always be the constant c.

Step-by-step explanation:

Looking at #16, that would be

f(x) = x^(2) + 4

y -intercept : (0, 4)

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.