Answer quickly for 5 stars and

emilio wants to invest $15,820 that he just received as a prize from a contest he entered. he researches certificates of deposit (cds) at two different banks. the details for his two best options are in the table below. both cds earn compound interest, which you worked on in exponential growth & decay. when interest is compounded, it is added to the account’s principal to become part of the money that earns interest.

1. determine which investment will earn emilio more interest.
first bank or bank west

2. how much more interest will he earn with that investment?

Bank West

$242.82

Step-by-step explanation:

To find which bank will yield more interest for Emilio, we can solve for the interest of each bank by using the Compound interest formula:

For the Bank West we have:

n = 4 Quarterly

t = 6 years

r = 3.8% or 0.038

P = 15820

Let's substitute them in the formula.

Now let's solve for the Interest. We subtract our total amount to the principal amount.

Interest = 19849.89 - 15820

Interest = 4029.89

Now let's solve for the First Bank.

n = 12 Monthly

t = 5 years

r = 4.3% or 0.043

P = 15820

Let's substitute them in the formula.

Now for the interest:

Interest = 19607.07 - 15820

Interest = 3787.07

This gives us:

Bank West Interest = $4029.89

First Bank Interest = $3787.07

So Bank West will earn more interest than First Bank.

To find how much more interest we subtract the interest of Bank West to First Bank.

4029.89 - 3787.07 = $242.82

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}