The length of a rectangle is 2 inches more than 4 times the width. the perimeter is 64 inches. find the length and the width.

The width is 6 inches and the length is 26 inches.

Explanation:
L=4w+2, since the length is 2 more than 4 times the width.

The perimeter is given by P=2L+2w; using our equation for L, we have
P=2(4w+2)+2w.

Using the distributive property, we have
P=2*4w+2*2+2w
P=8w+4+2w.

Combining like terms, we have P=10w+4.

We know the perimeter is 64, so we have
64=10w+4.

Subtract 4 from both sides:
64-4=10w+4-4
60=10w.

Divide both sides by 10:
60/10 = 10w/10
6=w.

Substitute this into the equation for length: L=4*6+2=24+2=26

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

the value of x is equal to 0.

Answer:

$4034.40

step-by-step explanation:

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40