Mathematics, 04.08.2019 07:00, Fireburntbudder
Use the formula h = −16t2 + v0t. a ball is thrown straight upward at an initial speed of v0 = 56 ft/s. (a) when does the ball initially reach a height of 40 ft? (b) when does it reach a height of 77 ft? (c) what is the greatest height reached by the ball? (d) when does the ball reach the highest point of its path? (e) when does the ball hit the ground?
Answers: 2
Mathematics, 21.06.2019 19:50, Roshaan8039
Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
Answers: 3
Mathematics, 21.06.2019 22:00, afolmar2006
What is the solution to the system of equation graphed belowa.(0,-4)b.(2,5),1),-3)
Answers: 3
Use the formula h = −16t2 + v0t. a ball is thrown straight upward at an initial speed of v0 = 56 ft/...
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