The measure of one angle is eleven more than four times a number another angle is twice the first angles measure the sum of the measures of the angles are 195 degrees what is the measure of each angle

Answer=65° & 130°

195°=angle1+angle2
195°=(11+4x)+2(11+4x)
195°=33+12x
subtract 33 for both sides
162=12x
13.5=x

Now lets solve for the measure of the angles

angle1=11+4x
angle1=11+4(13.5)
angle1=11+54
angle1=65°

angle2=2(11+4x)
angle2=2(11+4(33.5))
angle2=2(11+54)
angle2=2(65)
angle2=130°

X, y, and z are the angles
so
x is 11 more than 4 times y
x=11+4y

z is twice the first angles measure
z=2x

the sum of the angles is 195
x+y+z=195

so we have
x=11+4y
z=2x
and
x+y+z=195
make everything y
subsitute 11+4y for x
11+4y+y+z=195
subsitute 2x for z
11+4y+y+2x=195
subsitute 11+4y for x
11+4y+y+2(11+4y)=195
distribute
11+4y+y+22+8y=195
group according to type
(4y+y+8y)+(11+22)=195
add like terms
13y+33=195
subtract 33 from both sides
13y=162
divide both sides by 13
y=12 and 8/13
subsitute
x=11+4y
x=11+4(12 and 6/13)
x=11+48 and 24/13
x=11+49 and 11/13
x=60 and 11/13
z=2x
z=2(60 and 11/13)
z=120 and 22/13
z=121 and 9/13

the angles are
12 and 6/13
60 and 11/13
121 and 9/13 or aprox

12.46
60.85
121.69