How many real solutions does 5x^2+7x+1=0 have? explain your answer.

2

Step-by-step explanation:

The graph of 5x^2+7x+1 crosses the x-axis (x=0) twice, so there are 2 real solutions.

_____

The discriminant is b^2 - 4ac, where a=5, b=7, c=1. Its value is ...

... 7^2 -4·5·1 = 29

This value is greater than 0, indicating there are two (2) real roots. They are ...

... (-7±√29)/10

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

i would you but i don't under stand the qustion

step-by-step explanation: