9a-18b+21c apply distributive property to factor out gcf of all three terms

Step-by-step explanation:

We are asked to factor out GCF of expression using distributive property.

We can see that greatest common factor of each term of our given expression is 3.

Using distributive property , we will factor out 3 from our expression as:

Therefore, our required expression would be .

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.