Bruce has a pet worm that fell into a well. the well is 37 feet deep. each day, the worm climbs up 7 feet, but each night, it slides back down 2 feet. how many days will it take for bruce’s worm to get to the top of the well

7 days.

Step-by-step explanation:

Given,

The depth of the well = 37 feet,

Also, each day, the worm climbs up 7 feet, but each night, it slides back down 2 feet.

Thus, the total vertical distance covered by it in a day = 7 - 2 = 5 feet,

Now, since, at the last 7 feet it will not slide back,

Thus, the distance it has to cover at the rate of 5 feet per day = 37 - 7 = 30 feet,

So, the time taken by it to cover 30 feet = = 6 days,

Hence, the total time taken by it = the time taken by it to cover 30 feet + The time taken to climb up last 7 feet

= 6 days + 1 day

= 7 days.

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

step-by-step explanation:

the answer is 128