Mathematics

Mathematics, 04.08.2019 14:40, 19dansiste

Solve the differential equation: dy/dx = 4y2x 1 /3 a. 1 / y = 3x 4 /3 + c/ y 2 b. 1 /y = 3x 4 / 3 + c c. - 1 / y = 3x 4 /3 + c/ y 2 d. - 1 /y = 3x 4 / 3 + c

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Solve the differential equation: dy/dx = 4y2x 1 /3 a. 1 / y = 3x 4 /3 + c/ y 2 b. 1 /y = 3x 4 / 3 +...

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