The sum of two numbers is 70. their difference is two less than the smaller number. what are the numbers?

24 and 46

Step-by-step explanation:

Let x be the smaller number

x+y =70

y-x =x-2

Add x to each side

y-x+x = x+x-2

y = 2x-2

Substitute into the first equation

x+y =70

x+ (2x-2) =70

Combine like terms

3x-2=70

Add 2 to each side

3x-2+2 = 70+2

3x = 72

Divide by 3

3x/3 =72/3

x = 24

y = 2x-2

y = 2(24)-2

y =48-2

y = 46

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.