Quadrilateral abcd has vertices a(1, -3) , b(2, 1), c(6, 3), and d(7, -1). prove or disprove that the quad abcd is a rectangle.

If AC=BD, than Quad ABCD is a rectangle
AC
√(3+3)²+(6-1)²
√6²+5²
√36+25
√61
BD
√(1+1)²+(2-7)²
√2²+(-5)²
√4+25
√29
Quad ABCD is not a rectangle because √61 and √29 are not equal.

Use a calculator basically

1+1=22×1=22-1=11-1=1duh