Find the equation of the tangent line to f(x)=(x-1)5 at the point where x=2.

F(x)=(x-1)⁵, f'(x)=5(x-1)⁴. When x=2, f'(x)=5 the gradient of the tangent line. f(2)=1.
Let y=5x+c, and 1=10+c, when we plug in (2,1), c=-9 so the equation of the tangent line is y=5x-9.

We’re gonna need a picture to refer to in order to figure it out. try reposting your question with the picture included.