What is the equation in standard form of the line that passes through the point (4,-8) and has a slope of 1/4

The equation, in standard form, of the line that passes through the point (4, -8) and has a slope of 1/4 is:

The point-slope equation of a line passing though the point (x₁, y₁) and which has a slope m is given as:

y  -  y₁   =  m(x  -  x₁)

The line described passes through the point (4, -8) and has a slope of 1/4.

That is:

m = 1/4

x₁  =  4

y₁  =  -8

Substitute these values into the point-slope form of the equation of a line

Therefore, the equation, in standard form, of the line that passes through the point (4, -8) and has a slope of 1/4 is:

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just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

step-by-step explanation: mark as brainlest reallly need it thx