Plz me with this problem i don't have that much nine students choose integers. here are 7 of them: 5,-8, 10,-1 -12 ,-20 and 1. a. when all nine integers are ordered from least to greatest, the middle integer is 1. describe the integers chosen by the other two students. b. when all nine integers are ordered from least to greatest, the middle integer is -3. describe the integers chosen by the other two students.

A. Order the numbers so that 1 is in the middle:

-20, -12, -8, -1, 1, 5, 10, x, x -> The other 2 numbers must be greater than 1, as the range can be 2 < x, x being the number chosen

B. Order the numbers so that -3 is in the middle:

x, -20, -12, -8, (-3), -1, 1, 5, 10 -> The other number must be less than -3, as the range is x < - 3, x being the number chosen

hope this helps

answer: give more info

step-by-step explanation:

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong