What is the additive inverse of the complex number –12 + 4i?

The additive inverse of any number a is some number (-a) that makes the statement a + (-a) = 0 true.if we break up the complex number by parts and try to get each part to 0, we find that -12 + 12 = 0, and 4i + (-4i) = 0. putting those additive inverses together, we find that the additive inverse of -12 + 4i is 12 - 4i.

It has a slope of 1 nd a y intercept of -2

I'm not sure exactly but my best guess would be 1/4