[tex]rac{1}{x^2+3x-4} - rac{1}{x^2-3x+2}[/tex][tex]rac{ 3}{x^2-4} - rac{x+5}{x+2}[/tex]

The first one is and the second one is ;; it's tricky because the denominators aren't the same. You...

Mathematics, 03.08.2019 08:00, larenhemmings

$\frac{1}{x^2+3x-4} - \frac{1}{x^2-3x+2}$ $\frac{ 3}{x^2-4} - \frac{x+5}{x+2}$

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[tex]\frac{1}{x^2+3x-4} - \frac{1}{x^2-3x+2}[/tex][tex]\frac{ 3}{x^2-4} - \frac{x+5}{x+2}[/tex]...