Solve the system of linear equations by substitution. 8x−1/3y=0; 12x+3=y !

Substitution involves replacing part of one equation with the other equation. In this case, the second equation is already solved for y. All we have to do is replace y in the first equation with 12x+3.

8x - (1/3)(12x+3) = 0

Distribute the -1/3

8x - 4x - 1 = 0

4x - 1 = 0

4x = 1

x = 1/4

Now plug 1/4 in for x to solve for y.

12(1/4) + 3 = y

y = 6

(1/4, 6)