Atriangle has an area of 10 square meters. the height of the triangle is 5 meters. what is the base length of the triangle? 2 m 4 m 5 m 15 m

4 meters would be your answer, hope this helped

A= 1/2bh

Plug in the area and the height.

10= 1/2b(5)

Divide by 5 on both sides.

2= 1/2b

Divide by 1/2.

4=b

The base is 4 meters.

I hope this helps!
~kaikers

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12