Write an equation of the line that passes through the given points. (-2,8) and (1,2) (write answer in slope-intercept form.)

The slope-intercept form of the line that passes through the points (-2,8) and (1,2) is y=-2x+4

Step-by-step explanation:

Given:  

Points(x,y)= )= (-2,8)

Points(x1,y1)=  (1,2)

To find:

Equation in slope-intercept form=?

Solution:

The slope intercept form of a line is y= mx + b  

Where m= the slope

STEP 1: Finding the slope value

Substituting the points in the formula we get,  

STEP 2: Finding the value of  b

Substituting the slope value in the equation we have

y=mx+b,

y= -2(x)+b

y= -2(x) + b

substituting x and y from the points given,

8=-2(-2) + b

8=4+b

8-4=b

b =4

STEP 3: Formation of slope intercept equation

Substituting b and m in the equation of slope we get,

y= mx + b  

y= -2x+4.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

there is no question content here, but you for the free points! : d