One root of f(x)=x3+10x2-25x-250=-10. what are all the roots of the function? use the remainder theorem. x = –25 or x = 10 x = –25, x = 1, or x = 10 x = –10 or x = 5 x = –10, x = –5, or x = 5

option d is correct x = –10, x = –5, or x = 5    

step-by-step explanation:

given : function -

one root x=-10

the remainder theorem : solve the polynomial through long division.

using formula   p(x) = (x – a) q(x)   +   r(x).

where, p(x) is the dividend , (x-a) is the divisor or root , q(x) is the quotient , r(x) is the remainder

now we solve the given function using remainder theorem

,

when remainder is zero our quotient =

i.e,

solve  

therefore, roots of function is -10,5 or-5

hence, option d is correct x = –10, x = –5, or x = 5

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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