Y= x2 − 6x + 8 2y + x = 4 the pair of points representing the solution set of this system of equations is

2y + x = 4
x = -2y + 4

y = x^2 - 6x + 8
y = (-2y + 4)^2 - 6(-2y + 4) + 8
y = (-2y + 4)(-2y + 4) + 12y - 24 + 8
y = 4y^2 - 8y - 8y + 16 + 12y - 24 + 8
y = 4y^2 - 4y 
4y^2 - 4y - y = 0
4y^2 - 5y = 0
y(4y - 5) = 0
 
y = 0                x = -2y + 4
                        x = -2(0) + 4
                        x = 4

4y - 5 = 0          x = -2y + 4
4y = 5               x = -2(5/4) + 4
y = 5/4              x = -10/4 + 4
                         x = -10/4 + 16/4
                         x = 6/4 which reduces to 3/2

so u have 2 sets of points that will work

(4,0) and (3/2,5/4) <===

Its d so thats how it would would back from 1.0 form three four two

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