What does the graph of y = (x + 2)(x + 1)(x – 3)2 do near the point (3, 0)? the graph is the x-axis to its left, then , and is the x-axis to its right.

I am not completely sure but I think the answer is The graph is  

below  the x-axis to its left, then  is tangent to the x-axis at the point , and is  

above  the x-axis to its right.

Step-by-step explanation:

i graphed it and analyzed it i could be wrong tho.

i you goofed up when writing this, because hnot is not a word minusf is not either. i cannot answer   because of that.

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source