If f(x) is a continuous function defined for all real numbers, f(–10) = –2, f(–8) = 5, and f(x) = 0 for one and only one value of x, then which of the following could be that x value? a) -7 b) -9 c) 0 d) 2

B

Step-by-step explanation:

At x = -10 the function has a value of -2 (negative)

At x = -8, the function has a value of 5 (positive)

So that means the function, when graphed, would have to cross the x-axis between x = -10 and x = -8 for it go from Negative to Positive (jump). That value would be between -10 and -8.

From the answer choices, "-9" is the only value between -10 and -8. At this point, the function cuts the x-axis, or the point where "f(x) = 0".

correct choice B

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2