For the function f(x) = –(x 1)^2 + 4, identify the vertex, domain, and range.
a. the vertex is (–1, 4), the domain is all real numbers, and the range is y ≥ 4.
b. the vertex is (–1, 4), the domain is all real numbers, and the range is y ≤ 4.
c. the vertex is (1, 4), the domain is all real numbers, and the range is y ≥ 4.
d. the vertex is (1, 4), the domain is all real numbers, and the range is y ≤ 4.

The vertex is at -b/(2A). if you use the foil method it will come out to -(x^2+2x+1)+4. then distribute the negative and simplify the equation (add the four) the equation comes out to be -x^2-2x+3. The vertex is at x=2/(2*-1), which is -1. plug -1 into the original equation to find y, (y=-(-1)^2-2*(-1)+3) which is y=4. so the vertex is at (-1,4). then since the parabola opens down (negative a value) and has a maximum at 4, y is always less than or equal to 4. x is all real numbers as it goes on forever. so b is your answer.

====================



------------------------------------------



--------------------------------------------

There are 8,654 left