Write an equation of the line passing through point p that is perpendicular to the given line. p(3,1), y=13x−5

The slope of a line perpendicular to another is (-1) multiplied by the

reciprocal of the slope of the other line.

Reasons:

The equation of the given line is; y = 13·x - 5

The point through which the perpendicular line passes = P(3, 1)

Solution:

The slope of a line, b, perpendicular to a line a with slope m is

The equation of the given line, y = 13·x - 5, is given in slope and intercept form, y = m·x + c

Therefore, the slope, m = 13

The slope of the perpendicular line in therefore,

Which gives the equation of the perpendicular line in point and slope form as follows;

13·y - 13 = 3 - x

13·y = 3 - x + 13 = 16 - x

The equation of the line is 13·y = 16 - x

Learn more about the equation of a line perpendicular to another line here:

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all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: