Based on the graph shown, which of the following statements is true?
median < mode
median = mode
median > mode

The answer is:  [C]:  "median > mode" .

Explanation:

Note:

From looking at the given "bar chart" graph:

"100" occurs 14 times;
 
"200" occurs 6 times; 

"300" occurs 18 times;

"400" occurs 12 times; 

"500" occurs 2 times;

"600" occurs 12 times; 

"700" occurs 8 times;


So, the "mode" (the value the occurs the most often) is "300". 

The median; or "middle number":

Take this values (frequency in which they occur; in least to greatest) to repesent the actual values; for the purpose of determining the "median":

2, 6, 8, 12, 12, 14, 18 

The representative value for the median is "12" ; which corresponds to:

"400" and "600" ;   

So, in this case, we calculate the "median" by taking the "mean" of these two (2) values:
 
  mean = (sum of the values) ÷ (number of values being added) ;

            = (400 + 600) / 2  =  1,000 / 2 = 500.

The median is:  "500" .

The mode is:  "300" .

Note that:  "500 > 300" ;
 
So; the "median > mode" ; which is:

 Answer choice:  [C]:  "median > mode" .

Ifound this on google “a skewed (non-symmetric) distribution is a distribution in which there is no such mirror-imaging. a "skewed right" distribution is one in which the tail is on the right side. a "skewed left" distribution is one in which the tail is on the left side. the above histogram is for a distribution that is skewed right.” i hope this you for what your looking for