Mathematics, 30.07.2019 13:30, trujillo03

If y = 5x − 4, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs? (4 points) select one: a. {(0, −4), (2, 6), (4, 20)} b. {(0, −4), (2, 6), (4, 16)} c. {(0, 4), (2, 6), (4, 16)} d. {(0, 4), (2, −6), (4, 20)} thx

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answered: juanmias

{(0, -4), (2, 6), (4, 16)}

Step-by-step explanation:

we know that

If a set of ordered pairs represent possible inputs and outputs of the function

then

all ordered pairs of the set must be satisfy the function

we have

y=5x-4

case A) {(0, -4), (2, 6), (4, 20)}

Point (0, -4)

Substitute the value of x and the value of y in the function

-4=5(0)-4

-4=-4 -----> is true

Point (2, 6)

Substitute the value of x and the value of y in the function

6=5(2)-4

6=6 -----> is true

Point (4, 20)

Substitute the value of x and the value of y in the function

20=5(4)-4

20=16 -----> is not true

therefore

The set case A) not represent possible inputs and outputs of the function

case B) {(0, -4), (2, 6), (4, 16)}

Point (0, -4)

Substitute the value of x and the value of y in the function

-4=5(0)-4

-4=-4 -----> is true

Point (2, 6)

Substitute the value of x and the value of y in the function

6=5(2)-4

6=6 -----> is true

Point (4, 16)

Substitute the value of x and the value of y in the function

16=5(4)-4

16=16 -----> is true

therefore

The set case B) represent possible inputs and outputs of the function

case C) [tex{(0, 4), (2, 6), (4, 16)}[/tex]

Point (0, 4)

Substitute the value of x and the value of y in the function

4=5(0)-4

4=-4 -----> is not true

therefore

The set case C) not represent possible inputs and outputs of the function

case D) {(0, 4), (2, -6), (4, 20)}

Point (0, 4)

Substitute the value of x and the value of y in the function

4=5(0)-4

4=-4 -----> is not true

therefore

The set case D) not represent possible inputs and outputs of the function

answered: Guest

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answered: Guest

answer: yes i agree that you should not put it on/p>

step-by-step explanation: the reason for this is that it wastes other peoples time and also make them fail as well and that is never good.