While playing a board game, you roll two different colored standard dice. what is the probability of rolling a 5 on the black die and a number less than 4 on the red die? 1 10 1 12 2 3 1 2

Answer is 1/12

Step-by-step explanation:

sample space of rolling a die is={1,2,3,4,5,6}

A: rolling a 5 on the black die

A:{5}

hence, P(A)=1/6

B: rolling a number less than 4 on red die

B:{1,2,3}

hence, P(B)=3/6

A∩B: rolling a 5 on the black die and a number less than 4 on the red die

Since, both events are independent

Hence, P(A∩B)=P(A)×P(B)

                      =1/6×3/6

                       =1/12

hence, probability of rolling a 5 on the black die and a number less than 4 on the red die is 1/12

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: