1. translate the phrase “nine more than two times a number” into an algebraic expression.
a. 9x +2
b. 2x +9
c. 9x – 2
d. 2x – 9
2. evaluate the expression 3m – 5 when m = 7.
a. 2
b. 16
c. 21
d. 18
3. simplify 4x+ 8y – 3x +2 y.
a. 12x – y
b. 11x + y
c. 6x + 5 y
d. x + 10y
4. factor 24p +64.
a. 24(p+ 40)
b. 12 (2p + 5)
c. 8( 3p + 8)
d. 3 (8p +21)
5. for problems 5 to 12, use properties of equality to solve the equation.
a. -30
b. 14
c. -14
d. 30
6. w – 8 = -12
a. -20
b. -4
c. 4
d. 20
7. 3q = 12
a. 4
b. 9
c. 15
d. 36
8. q/6 = 24
a. 4
b. 8
c. 30
d. 144
9. 3b – 9 =15
a. 8
b. 6
c. 2
d. -2
10. y/5 + 10 = -15
a. -125
b. -25
c. -5
d. -1
11. -3 (4-a)=6
a. -6
b. -2
c. 2
d. 6
12. 5(x+6)=45
a. 15
b. 3
c. -3
d. -15
13. brandon is bringing bottled water to a picnic. he has 4 full cases of bottles of water, and a bag with 8 more bottles. he has a total 104 bottles of water. write and solve an equation to find the number of bottles in each case.
a. x/4 + 8= 104; x= 384
b. x/4 – 8 = 104; x = 448
c. 4x +8 = 104; x = 24
d. 4x – 8 = 104; x=28
14. which is a solution of h > -6?
a. -10
b. -8
c. -6
d. -4
15. z- 4 > 9
a. z> -13
b. z > -5
c. z > 5
d. z > 13
16. z – 4 > 9
a. z> -13
b. z> -5
c. z> 5
d. z> 13
17. q + 7 < - 15
a. y< 3
b. y> 3
c. y< -3
d. y > -3
18. -3y > 9
a. y< 3
b. y > 3
c. y< -3
d. y> - 3
19. k/5 > -4
a. k > -20
b. k< -20
c. k > 20
d. k < 20
20. 4g – 8 < 20
a. g> 3
b. g< 3
c. g > 7
d. g< 7
21. v/-2 + 12 < 8
a. v > 8
b. v< 8
c. v > -8
d. v< -8
plz me plz give me the write answers plz its worth 18 points!

The correct answers are:

#1) B - 2x+9

#2) B - 16

#3) D - x+10y

#4) C - 8(3p+8)

#5) No equation, cannot be done

#6) B - w = -4

#7) A - q = 4

#8) D - q = 144

#9) A - b = 8

#10) A - y = -125

#11) D - a = 6

#12) B - x = 3

#13) C - x = 24

#14) D - -4

#15) D - Z>13

#16) same as 15

#17) Not listed; Q < -22

#18) C - y < -3

#19) A - K>-20

#20) D - g< 7

#21) A - V > 8

Explanation:

#1) "Nine more than" means something plus 9. "Two times a number" means 2x. Together, this gives us 2x+9.

#2) For 3m-5 if m=7, substitute 7 for m. 3(7)-5 = 21-5 = 16.

#3) To simplify 4x+8y-3x+2y, combine like terms. We can use the commutative property to rewrite the like terms together: 4x-3x+8y+2y. Combining like terms, we have x+10y.

#4) To factor, we pull out the GCF. To find the GCF, we find the prime factorization of 24 and 64:

24 = 2(12) = 2(4)(3) = 2(2)(2)(3)

64 = 2(32) = 2(4)(8) = 2(2)(2)(2)(4) = 2(2)(2)(2)(2)(2)

They have 3 2's in common, so the GCF is 2(2)(2) = 8. Pulling this out of our expression, we have:

24p+64 = 8(3p+8)

#5) We have no equation to solve.

#6) We add 8 to each side:

w-8+8 = -12+8; w = -4

#7) We divide both sides by 3:

3q/3 = 12/3; q = 4

#8) We multiply both sides by 6:

(q/6)(6) = 24(6); q = 144

#9) 3b-9 = 15

First, add 9 to each side:

3b-9+9 = 15+9; 3b = 24

Now divide both sides by 3:

3b/3 = 24/3; b = 8

#10) y/5 + 10 = -15

First subtract 10 from both sides:

y/5+10-10 = -15-10; y/5 = -25

Now multiply both sides by 5:

(y/5)(5) = -25(5); y = -125

#11) -3(4-a) = 6

First use the distributive property:

-3(4) - -3(a) = 6; -12+3a = 6

Add 12 to each side:

-12+3a+12 = 6+12; 3a = 18

Divide both sides by 3:

3a/3 = 18/3; a = 6

#12) 5(x+6) = 45

Use the distributive property:

5(x)+5(6) = 45; 5x+30=45

Subtract 30 from each side:

5x+30-30 = 45-30; 5x=15

Divide both sides by 5:

5x/5 = 15/5; x = 3

#13) 4x+8=104

Subtract 8 from each side:

4x+8-8 = 104-8; 4x=96

Divide both sides by 4:

4x/4 = 96/4; x = 24

#14) We want a number larger than -6. For negative numbers, this means a number closer to 0; the number closest to 0 is -4.

#15) Add 4 to each side: z-4+4 > 9+4; z > 13

#16) Same as 15

#17) Subtract 7 from each side: q+7-7<-15-7; q<-22

#18) Divide both sides by -3 (remember, when you multiply or divide an inequality by a negative number, you must flip the inequality symbol): -3y/-3>9/-3; y<-3

#19) Multiply both sides by 5: (k/5)(5)>-4(5); k>-20

#20) 4g-8<20

First add 8 to each side: 4g-8+8<20+8; 4g<28

Divide both sides by 4: 4g/4<28/4; g<7

#21) v/-2 +12 < 8

First subtract 12 from each side: (v/-2)+12-12<8-12; (v/-2)<-4

Multiply both sides by -2 (remember to flip the inequality symbol): (v/-2)(-2)<-4(-2); v>8

Question 1:

Assume that the number is x

Two times a number is 2x and 9 more means that we will add 9

This gives us : 2x + 9 > option B

Question 2:

We are given the expression: 3m-5. To find the value of the expression at m = 7, all we have to do is substitute in the expression with the given value.

This gives us: 3(7) - 5 = 21 - 5 = 16 > option B

Question 3:

The given expression is 4x+8y-3x+2y. To simplify the expression, we will group the like terms (terms having the same variable raised to the same degree)

This gives us: x(4-3) + y(8+2) = x + 10y > option D

Question 4:

The given expression is: 24p + 64. To factor the expression, we will need to take out the common factor from both numbers and then use distributive property. We can note that both numbers are divisible by 8.

This gives us: 8() = 8(3p+8) > option C

Question 6:

We are given that W-8=-12. To isolate the W we will simply add 8 to both sides.

This gives us: W-8+8 = -12+8 > W = -4 > option B

Question 7:

We are given that 3q=12. To isolate q, we will simply divide both sides by 3.

This gives us: > q=4 > option A

Question 8:

We are given that . To get the value of q, we will simply multiply both sides by 6.

This gives us: > q=144 > option D

Question 9:

We are given that: 3b-9=15. To get the value of b, we will first add 9 to both sides of the equation and then divide both sides by 3.

This gives us: 3b-9+9=15+9 > 3b=24 > b= > option A

Question 10:

The given is: . To get the value of y, we will first subtract 10 from both sides and then multiply both sides by 5.

This gives us: > y = -25*5 = -125 > option A

Question 11:

The given is: -3(4-a=6). To get the value of a, we will first divide both sides by -3, then subtract 4 from both sides and finally multiply both sides by -1

This gives us: 4-a = > -a=-2-4=-6 > a=6 > option D

Question 12:

The given is: 5(x+6)=45. To get the value of x, first we will divide both sides of the equation by 5 and then subtract 6 from both sides.

This gives us: x+6 = > x = 9-6 = 3 > option B

Question 13:

Assume that the number of bottles is x.

He has 4 full bags of bottles. This means that number of bottles in bags = 4x

He has additional 8 bottles.

The total number of bottles is 104

This means that total number of bottles is 4x+8 = 104

Now, we solve the equation:

4x+8-8 = 104-8 > 4x=96 > x= > option C

Question 14:

Note that on the negative axis, the number decreases as its value increases (this is opposite to the positive counting). In other words: -1 > -2 and -2>-3 and so on.

This means that for h>-6 > h could be -4 > option D

Question 15 & 16:

The given is: Z-4>9. To get the value of Z, Add 4 to both sides of the equation.

This gives us: Z-4+4 > 9+4 > Z>13 > option D

Question 17:

The given is: Q+7 < -15. To get the value of Q, subtract 7 from both sides.

This gives us: Q+7-7 < -15-7 > Q < -22

Question 18:

The given is: -3y>9. To get the value of y, we will divide both sides by -3. Remember that when we divide by a negative number, we flip the inequality sign. This means that the > will be flipped to <

This gives us: > option C

Question 19:

The given is: -4. " class="latex-formula" id="TexFormula12" src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bk%7D%7B5%7D%20%3E%20-4.%20" title=" \frac{k}{5} > -4. "> To get the value of k, we will multiply both sides of the equation by 5.

This gives us: k > -4(5) > k > -20 > option A

Question 20:

The given is: 4g-8<20. To get the value of g, we will first add 8 to both sides of the equation and then divide both sides by 4.

This gives us: 4g<28 > g< > g<7 > option D

Question 21:

The given is: . To get the value of v, first we will subtract 12 from both sides of the equation, then we will multiply both sides by -2 (remember to flip the inequality sign since we are multiplying by a negative number)

This gives us: > option A

Hope this helps :)

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula