What can be concluded about a line that passes through the points (1, -2) and (4, -2) check all that apply. the slope is 0. the y-intercept is -2. the line is vertical. the line is horizontal. the line has no y-intercept. the equation of the line is y = -2

 The correct options are

(A) The slope is 0.

(B) The y-intercept is -2.

(C) The line is horizontal.

(D) The equation of the line is y = -2

Step-by-step explanation:  We are given to select the statements that can be concluded about a line that passes through the points (1, -2) and (4, -2).

We know that

the slope of a line passing through the points (a, b) and (c, d) is given by

So, the slope of the given line is

Since the line passes through the point (1, -2), so its equation will be

Comparing with the slope-intercept form y=mx+c, we get

y-intercept, c = -2.

Also, the line is of the form y = a, which is parallel to the x axis, so the given line is horizontal.

Thus, the correct options are

(A) The slope is 0.

(B) The y-intercept is -2.

(C) The line is horizontal.

(D) The equation of the line is y = -2

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

miss u!

- nicole