In the following equation a & b are both integers. what is the value of a? what is the value of b?

3ax-8a=b-18x
3ax+18x=b+8a
3x(a+6)=b+8a

3x=(b+8a)/(a+6)
x=(b+8a)/3(a+6)
3a*(b+8a)/3(a+6)=b-18*(b+8a)/3(a+6)
a(b+8a)/(a+6)=b-6(b+8a)/(a+6)
a(b+8a)=b(a+6)-6(b+8a)
ab+8a^2=ab+6b-6b-48a
ab+8a^2=ab-48a
8a^2=-48a
8a^2+48a=0
8a(a+6)=0 so a=0,-6
0=b-18x or -18x+48=b-18x
-b=-18x or 48=b
let b=18 if a =-6