Mathematics
Mathematics, 28.07.2019 17:50, savannahvargas512

(√50 + √2) which statement is true about the expression? 1) it is irrational and equal to 2√13 2) it is irrational and equal to 6√2 3) it is rational and equal to 2 4) it is rational and equal to 6

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Mathematics, 13.07.2019 03:30, Weser17
Fill in the blanks of the following proof by contradicition that 7 + 4√2 is an irrational number. (you may use the fact that √2 is irrational.) proof: suppose not. that is suppose that 7 + 4√2 is (i) by definition of rational, 7 + 4√2 = a/b, where (ii) multiplying both sides by b gives 7b + 4b√2 = a so if we subtract 7b from both sides we have 4b√2 = (iii) dividing both sides by 4b gives √2 = (iv) but then √2 would be rational number because (v) this contradicts our knowlegde that √2 is irrational. hence the supposition is false and the given statement is true. a. (i). rational (ii). a and b are integers and b cannot equal 0 (iii). a+7b (iv). (a+7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a rational number. b. (i). irrational (ii). a and b are integers and b cannot equal 0 (iii). a-7b (iv). (a-7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a irrational number. c. (i). irrational (ii). a and b are integers and b cannot equal 0 (iii). a-7b ( a-7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a rational number. d. b. (i). rational (ii). a and b are integers and b cannot equal 0 (iii). a-7b ( a-7b)/4b (v). both a-7b and 4b are integers (since products and differences of interger are integers) and so √2 would be a rational number.
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(√50 + √2) which statement is true about the expression? 1) it is irrational and equal to 2√13 2)...

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