What are the endpoint coordinates for the midsegment of
△jkl that is parallel to line jl?

Step-by-step explanation:

The midsegment of △JKL that is parallel to line JL, it's a segment that begins at JK side and ends at LK side. This means we just need to find the coordinates of JK and LK midpoints.

The formula for midpoints is

So, for JK, points are J(1,4) and K(4,1). Replacing in the formula, we have

For LK, points are L(0,-1) and K(4,1)

This means that the endpoint coordinates for the midsegment that is parallel to JL are (2.5, 2.5) and (2,0).

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!