For the function f(t) = pe^rt, if p= 6 and r = 0.06, then what is the value of f(6) to the nearest tenth? a. 219.6 b. 8.6 c. 0.1 d. 2.2

B. 8.6 Let's substitute the given values into the function and calculate the result. So: f(t) = Pe^rt f(t) = 6e^0.06t f(6) = 6e^(0.06*6) f(6) = 6e^(0.36) f(6) = 6*1.433329415 f(6) = 8.599976487 Rounding to the nearest tenth, gives: 8.6 So the answer is "B. 8.6"

The answer for this is 9/1253decimal form 0.007