Andrew designed a square-shaped logo for a client using his new computer program. he wants to edit the design to increase the length by 20 pixels. the area of the new design is given by the quadratic expression below, where x is the width of the original design. x^2+20x match each part of the polynomial with what it represents. > > x + > > a).the area of the original design b).the length of the new design c).the width of the new design d).the difference in the lengths of the designs

x2>

A).the area of the original design.  
Rememeber that x= original width. Since it's a square, length equals width. The area of a square is any side squared, so the area is x². 

x>
C) The width of the new design. The width doesn't change, only the length does, and x has been defined as the original width. Therefore, x is both the orinignal width and the width of the new design. 

x + 20>

B) The length of the new design. In the original design, which is a square, x = width = length. When the designer increased the length by 20, the new length is x + 20. 

20>

D) The difference in the lengths of the designs. The length increases by 20, so 20 is the difference in the lengths of the original and new design.