An expression is shown below: f(x) = 2x2 − 5x + 3 part a: what are the x-intercepts of the graph of f(x)? show your work. (2 points) part b: is the vertex of the graph of f(x) going to be a maximum or minimum? what are the coordinates of the vertex? justify your answers and show your work. (3 points) part c: what are the steps you would use to graph f(x)? justify that you can use the answers obtained in part a and part b to draw the graph. (5 points)

F(x) = 2x^2 - 5x + 3a. the zeros or x intercepts are 1 and 1.5. we can use the quadratic equation to solve this problem.(5 +- 1)/4 = 1.5 or 1b. the vertex of the graph is a minimum because there is a positive sign in front of the equation meaning that the graph opens up.c. we know the y intercept is 3 as given in the equation so we plot down the x intercepts and the y intercepts. by law of access of symmetry(the vertical line that goes down the vertex, whatever number is on one side, the opposite must be on the other. so our graph would have points, 1,0 1.5,0 0,3 3,-3