Scores on a standardized test are normally distributed with a mean of 350 and a standard deviation of 25. approximately what percent of students scored between 360 and 380?

22.95 %

Step-by-step explanation:

Given : Scores on a standardized test are normally distributed with

Mean :

Standard deviation :

The formula to find z-score:-

For x=360

For x=380

The p-value =

In percent , the percent of students scored between 360 and 380 =

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step-by-step explanation:

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step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)