Find two consecutive even integers such that the sum of the smaller and five times the larger is 202

Let's define our two even integers as "x" and "x+2", as they have to be consecutive. Next, let's convert these words into math. First, we know it has to be the sum of the smaller, or x, and five times the larger. So, we have x+ 5(x+2). Then, we know it equals 202, so we have x + 5x+ 10 = 202. We can clean up the left side by combining like terms and making it 6x+10 = 202. Next, we subtract 10 from both sides, getting us 6x = 192. We then divide both sides by 6, getting us 32. Therefore, the integers are 32 and 34. Hope this helped!