Statistics show that a certain soccer player has a 63% chance of missing the goal each time she shoots. if this player shoots twice, the exact probability that he scores a goal both times is __%

13.69%

Step-by-step explanation:

Given :Statistics show that a certain soccer player has a 63% chance of missing the goal each time she shoots

To Find :  If this player shoots twice, the exact probability that he scores a goal both times is __%

Solution:

Since  soccer player has a 63% chance of missing the goal each time she shoots.

probability of missing the goal is 63/100=0.63

since the sum of probabilities = 1

Thus 1 = probability of missing the goal +probability of scoring the goal

1 = 0.63+probability of scoring the goal

1-0.63 = probability of scoring the goal

0.37 =probability of scoring the goal

If this player shoots twice, the exact probability that he scores a goal both times is 0.37*0.37 = 0.1369

In percent = 0.1369*100=13.69%

Thus the exact probability that he scores a goal both times is 13.69%

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

srry ask agian

step-by-step explanation: