An academic department with five faculty members narrowed its choice for department head to either candidate a or candidate b. each member then voted on a slip of paper for one of the candidates. suppose there are actually three votes for a and two for b. if the slips are selected for tallying in random order, what is the probability that a remains ahead of b throughout the vote count (e. g., this event occurs if the selected ordering is aabab, but not for abbaa)?

The probability that the first two votes drawn are both for candidate a is given by:
3C2/5C2 = 3/10
Having drawn two votes for candidate a on the first two draws, there are 2 votes for candidate b and one vote for candidate a remaining. The probability that a vote for candidate b will be drawn on the third draw is:
2/3.
After the first three draws, there reains one vote for candidate a and one vote for candidate b. The probability that a vote for candidate a will be drawn on the fourth draw is:
1/2.
The probability of the ordering aabab is therefore given by:

The answer is: 0.1.

The answer is c because you turn 17.5% into a decimal which gives you .175 then you times that by $361.35 which gives you 63.23625 but then you round that which gives you 63.24. then you at 63.24 pulse 361.35 and you round it which gives you $425

There is no question, there is just the answer.