To decide whether two triangles are similar is it enough to know that two pairs of corresponding angle measures in the triangle are equal. explain your answer.

No, to decide whether two triangles are similar it is not enough to know that two pairs of corresponding angle measures in the triangle are equal.

That is because two triangles are similar if the only difference is size.

So, when you know that two corresponding angles are equal, the third angle is also (necessarily) equal. This is, the all three angles are equal and it could be the case that also the three corresponding side lengths are equal, which means that the triangles are not similar but congruent.

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4