Identify the triangle that contains an acute angle for which the sine and cosine ratios are equal.

we have to consider a triangle whose acute angle measure is 45° so that the sine and cosine ratios are equal.

Step-by-step explanation:

We need to consider a right angled triangle such that the measure of one of angle is 90° ,the second angle is 45° and hence the third angle could be found by using the fact that the sum of all the angles is 180°.

Hence we get the third angle measure to be 45°

( ∠1+∠2+∠3=180°

90+45+∠3=180

∠3=180-(90+45)

∠3=45° )

so in the right angled triangle if we use our trignometric identity along either angle 2 or angle 3 we get;

sin 45°=

and cos 45°=  

Hence the sine and cosine angle are equal.

So we have to consider a triangle whose acute angle measure is 45° so that the sine and cosine ratios are equal.

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.