The point-slope form of a line that has a slope of –2 and passes through point (5, –2) is shown below. y + 2 = -2 (x-5). what is the equation in slope-intercept form?

I'm going to say that it is y = -2x+8. Here's where I got that. I took the equation you gave me and multiplied it out using the distributive property on the right side. That got me y+2 = -2x + 10. Then, I subtracted the two from the left side and then subtracted the two from the right side. That left me with y = -2x + 8. Hope this helps.

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.