Which absolute value functions will be narrower than the parent function, f(x) = |x|? check all that apply. f(x) = |x| f(x) = |x – 2| f(x) = |x| + 3 f(x) = 2.9|x| f(x) = 1.2|x + 8| f(x) = 0.7|x| – 3.2

The absolute value functions narrower than the parent function are: f(x) = |x| - 3 and f(x) = 0.7|x| - 3.2. This conclusion can be obtained by substituiting any value of x (let x = 2).

Given :

Parent Function - f(x) = |x|

Put any value of x in the parent function and put the same value of x in the absolute value function to determine which absolute value function will be narrower than the parent function.

So, it can be conclude that the absolute value functions narrower than the parent function are: f(x) = |x| - 3 and f(x) = 0.7|x| - 3.2.

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