Mathematics

Mathematics, 26.07.2019 18:00, Ruchen

13. the distance from a point to a line is the length of the segment from the point to the line.

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Mathematics, 28.06.2019 09:10, talannajanis

I'm desperate use δabc to answer the question that follows: triangle abc. point f lies on ab. point d lies on bc. point e lies on ac. ad, be, and cf passes through point g. line ad passesgiven: δabcprove: the three medians of δabc intersect at a common point.when written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point: statements justifications point f is a midpoint of line segment ab point e is a midpoint of line segment ac draw line segment bedraw line segment fc by construction point g is the point of intersection between line segment be and line segment fc intersecting lines postulate draw line segment ag by construction point d is the point of intersection between line segment ag and line segment bc intersecting lines postulate point h lies on line segment ag such that line segment ag ≅ line segment gh by constructioni bgch is a parallelogram properties of a parallelogram (opposite sides are parallel)ii line segment fg is parallel to line segment bh and line segment ge is parallel to line segment hc midsegment theoremiii line segment bd ≅ line segment dc properties of a parallelogram (diagonals bisect each other)iv line segment gc is parallel to line segment bh and line segment bg is parallel to line segment hc substitution line segment ad is a median definition of a medianwhich is the most logical order of statements and justifications i, ii, iii, and iv to complete the proof? (4 points) aiv, ii, iii, i bii, iv, i, iii civ, ii, i, iii dii, iv, iii, i

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Mathematics, 14.07.2019 17:00, crimsonkiss

Use δabc to answer the question that follows: given: δabc prove: the three medians of δabc intersect at a common point. when written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point: statements justifications point f is a midpoint of line segment ab point e is a midpoint of line segment ac draw line segment be draw line segment fc by construction point g is the point of intersection between line segment be and line segment fc intersecting lines postulate draw line segment ag by construction point d is the point of intersection between line segment ag and line segment bc intersecting lines postulate point h lies on line segment ag such that line segment ag ≅ line segment gh by construction i bgch is a parallelogram properties of a parallelogram (opposite sides are parallel) ii line segment bd ≅ line segment dc properties of a parallelogram (diagonals bisect each other) iii line segment gc is parallel to line segment bh and line segment bg is parallel to line segment hc substitution iv line segment fg is parallel to line segment bh and line segment ge is parallel to line segment hc midsegment theorem line segment ad is a median definition of a median which is the most logical order of statements and justifications i, ii, iii, and iv to complete the proof? iii, iv, ii, i iv, iii, i, ii iii, iv, i, ii iv, iii, ii, i

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Mathematics, 24.07.2019 00:50, dbryrob9148

Given: δabc prove: the three medians of δabc intersect at a common point. when written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point: statements justifications point f is a midpoint of line segment ab point e is a midpoint of line segment ac draw line segment be draw line segment fc by construction point g is the point of intersection between line segment be and line segment fc intersecting lines postulate draw line segment ag by construction point d is the point of intersection between line segment ag and line segment bc intersecting lines postulate point h lies on line segment ag such that line segment ag ≅ line segment gh by construction i line segment bd ≅ line segment dc properties of a parallelogram (diagonals bisect each other) ii line segment fg is parallel to line segment bh and line segment ge is parallel to line segment hc midsegment theorem iii line segment gc is parallel to line segment bh and line segment bg is parallel to line segment hc substitution iv bgch is a parallelogram properties of a parallelogram (opposite sides are parallel) line segment ad is a median definition of a median which is the most logical order of statements and justifications i, ii, iii, and iv to complete the proof? ii, iii, i, iv iii, ii, i, iv ii, iii, iv, i iii, ii, iv, i

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Mathematics, 01.08.2019 08:00, chell6170

Given: δabc prove: the three medians of δabc intersect at a common point. when written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point: statements justifications point f is a midpoint of line segment ab point e is a midpoint of line segment ac draw line segment be draw line segment fc by construction point g is the point of intersection between line segment be and line segment fc intersecting lines postulate draw line segment ag by construction point d is the point of intersection between line segment ag and line segment bc intersecting lines postulate point h lies on line segment ag such that line segment ag ≅ line segment gh by construction i line segment bd ≅ line segment dc properties of a parallelogram (diagonals bisect each other) ii line segment fg is parallel to line segment bh and line segment ge is parallel to line segment hc midsegment theorem iii line segment gc is parallel to line segment bh and line segment bg is parallel to line segment hc substitution iv bgch is a parallelogram properties of a parallelogram (opposite sides are parallel) line segment ad is a median definition of a median which is the most logical order of statements and justifications i, ii, iii, and iv to complete the proof? ii, iii, i, iv iii, ii, i, iv ii, iii, iv, i iii, ii, iv, i

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