Acyclist bikes at a constant speed for 22 miles. he then returns home at the same speed but takes a different route. his return trip takes one hour longer and is 27 miles. find his speed

How concerned are you with how to get the answer?
Because I know the answer is 5 miles per hour
22/5= 4.4 hours
27/5= 5.4 hours

Alright this is how you solve it
Distance over time equals speed
So 22/y=x and 27/y+1=x
Start by solving for time by having these two equations equal each other
22/y=27/y+1
Cross multiply to get
22(y+1)=27y
22y+22=27y
Isolate Y
5y=22
Y=4.4
Now solve for X which is the speed, you can plug in Y to either of the two equations
22/4.4=x
X=5 miles per hour

200+150+100+50+19=519519÷60=$8.65$8.65-$5.00=$3.65 < -- answer