Acircle has a radius of 9 cm and a sector of the circle has an arc length of 9.7 cm.

the angle at the centre of the sector is x°.

calculate the value of x to the nearest degree.

The value of X is 62 degrees

Step-by-step explanation:

The arc length L  of a circle is given by formula:

L= 2(pi)(r)X / 360 (1)

where pi = 3.14, r is the radius of the circle and X the angle that produces the arc. You want the angle X so we can simplify X in equation (1)

360L=2(pi)(r)X

360L/2(pi)(r)= X

X =  360L/2(pi)(r)

We replace the radius r=9cm the arc L = 9.7 cm and pi and obtain

X = 360* (9.7 cm)/ 2(3.14)*(9cm) = 3492/56.52 = 61.78

That rounded to nearest degree is 62 degrees.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.