Why is the product of two rational numbers always rational? select from the drop-down menus to correctly complete the proof. let a/b and c/d represent two rational numbers. this means a, b, c, and d are (1) a. integers b. irrational numbers) and (2) a. b is not 0, d is not 0 b. b and d are 0) the product of the numbers is ac/bd , where bd is not 0. because integers are closed under (3) a. addition b. multiplication) ac/bd is the ratio of two integers, making it a rational number.

The answer is integer. The product or answer of two rationals is like getting or multiplying two fractions, which will have another fraction of this similar form as the outcome since integers are sealed under multiplication. All rational number can be indicated as q/r, with q and r are equally integers. Another enlightenment is the product of two rational numbers is a/b * c/d, with a, b, c, and d are integers. However, this is just (ac)/(bd), and ac nd bd are both outcomes of integers and therefore integers themselves. The product of two rational numbers can be considered as the quotient of two integers and is itself rational. So, multiplying two rational numbers yields another rational number.

the 4th choice is the correct one

step-by-step explanation:

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation: