Fis = 0.4 and fst = 0.8 and the average allele frequency p = 0.7, find the observed level of heterozygosity in the total population. a..2689, b..3743, c..0504, d..9827, e..5001

b.an increase in a causes b to decrease

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

i need a picure

step-by-step explanation: