Harper has $15.00 to spend at the grocery store. she is going to buy bags of fruit that cost $4.75 each and one box of crackers that cost $3.50. model the problem algebraically and determine the maximum number of bags of fruit, b, harper can buy.

Since Harper has only $15 that is the most she can spend.

That means we would have 15 > or = 4.75b + 3.5c.

The best way to solve this would be to divide,
15 ÷ 4.75 = 3.15

Then round down to the nearest whole number.

You should get 3 bags of fruit.

♥ Hope I helped ♥

You just need to add 32 to 14 and get 46.